Question

how many carbon dioxide molecules are produced if 8.45 x 1023 of water molecules of water are produced

Answer 1

The given question is incomplete. The complete question is:

Determine how many carbon dioxide molecules are produced if molecules of water are produced

`C_2H_6(g)+O_2 (g)\rightarrow CO2(g)+H_2O(g)`

Answer:
`5.60* 10^(23)` molecules of carbon dioxide are produced

Step-by-step explanation:

The balanced chemical equation is:

`2C_2H_6(g)+7O_2 (g)\rightarrow 4CO2(g)+6H_2O(g)`

`\text{Moles of water}=\frac{\text{given molecules}}{\text{Avogadros number}}=(8.45* 10^(23))/(6.023\\times 10^(23))=1.40moles`

Accoding to stoichiometry:

6 moles of water are produced along with = 4 moles of carbon dioxide

Thus 1.40 moles of water are produced along with =
`(4)/(6)* 1.40=0.93` moles of carbon dioxide

Molecules of carbon dioxide =
`moles* {\text {Avogadros number}}=0.93* 6.023* 10^(23)=5.60* 10^(23)`