Question

A ball is spun around in circular motion such that it completes 50 rotations in 25 s.

1) What is the period of its rotation?
2) what is the frequency of its rotation?

Answer 1

(A) The period of its rotation is 0.5 s (2) The frequency of its rotation is 2 Hz.

Step-by-step explanation:

Given that,

a ball is spun around in circular motion such that it completes 50 rotations in 25 s.

(1). Let T be the period of its rotation. It can be calculated as follows :

`T=(25)/(50)\\\\T=0.5\ s`

(2). Let f be the frequency of its rotation. It can be defined as the number of rotations per unit time. So,

`f=(50)/(25)\\\\f=2\ Hz`

Hence, this is the required solution.