Question

1. If the fare wos 10 cents, and

40,000 people boycotted the
buses, how much money did
the bus system lose in the first
day in 1956

Answer 1

The bus system in Montgomery, Alabama lost $4,000 on the first day of the boycott in 1956.

Step-by-step explanation:

In 1956, the fare for buses in Montgomery, Alabama was 10 cents. On the first day of the boycott, 40,000 people chose not to ride the buses. To calculate the amount of money lost by the bus system, we can multiply the fare by the number of people who boycotted the buses:

Money Lost = Fare x Number of people boycotting

Money Lost = $0.10 x 40,000

Money Lost = $4,000

Therefore, the bus system lost $4,000 on the first day of the boycott in 1956.