Answer:
Mean = 59
Median = 58
Explanation:
Given the data for a Javelin throw :
56, 58, 63, 57 61 meters
Reordering the data: 56, 57, 58, 61, 63
Mean, m = Σx / n
n = sample size = 5
m = (56 + 57 + 58 + 61 + 63) / 5
m = 295 / 5
m = 59
The median : 1/2 (n+1)th term
1/2(5 +1) the term
1/2(6) = 3rd term
Median value = 58