Answer:
![a_n=112 \cdot \left(\frac14 \right)^(n-1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/fkbflw8z2qtbir9zylwxuxue48hrcf7t90.png)
Explanation:
The difference between each term in the sequence is not the same, therefore the sequence is a geometric sequence.
Geometric sequence formula:
![a_n=a r^(n-1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/y3oc1tqrwf4xvom09aei38zqho7ufuhwmw.png)
where
is the start term and
is the common ratio
Given
![a_1 = 112 \implies a=112](https://img.qammunity.org/2023/formulas/mathematics/high-school/osdcebbvoy0w2mhng5jnn5w1pjdqd6qu3f.png)
To calculate
, divide one term by its previous term:
![\implies r=(a_3)/(a_2)=(7)/(28)=\frac14](https://img.qammunity.org/2023/formulas/mathematics/high-school/7sl3k4xfs5aco6foy7w6hc0ymrdpdulfk8.png)
Therefore,
![a_n=112 \cdot \left(\frac14 \right)^(n-1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/fkbflw8z2qtbir9zylwxuxue48hrcf7t90.png)