1) sinACD/12.9=sin86/16.358 = ?° 2) sin53/23.0333=sinDCB/12 = ?°

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asked Jan 26, 2023 160k views

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1) sinACD/12.9=sin86/16.358 = ?°

2) sin53/23.0333=sinDCB/12 = ?°

Mathematics
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Ogun asked

by Ogun

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Answer:

the answer is 2 sin53/23.0333=sinDCB/12 = ?°

Explanation:

Dwestgate answered Feb 1, 2023

by Dwestgate

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