Question

135 g of aluminum initially at 400.°C is added to an unknown mass of water (initially at 25°C). When thermal equilibrium is reached, the system has a temperature of 80.°C. Find the mass of water. Note c = .89 J/g°C for Al

Answer 1

981.82g or 0.982 kg

Step-by-step explanation:

I believe this is Physics, but okay!

We have to use the Specific Heat Capacity formula here.

Heat energy = mass x specific heat capacity x change in temperature

mass = Heat energy/(specific heat capacity x change in temperature)

Heat energy is measured in Joules so we need to find out how to do this.

To find an amount in Joules, we are given 135g and 0.89J/g°C.

135g x 400°C = 54000 to give us g°C

54000 x 0.89 = 48060 By multiplying these two values, we get given 48060J.

This is because: g°C/1 x J/g°C = Joules on it's own

mass = (48060)/[0.89 x (80 - 25)]

mass = 981.82g