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Write the sum using summation notation -1+2+5+8+...+44

1 Answer

1 vote

Answer:


\sum_(i=0)^(15) (3i-1)

Explanation:

for i=0 you have the first term, 3*0-1 = -1

for i=1 you have the second term, 3*1-1 = 2

...

for i=15 you have the last term, 3*15-1 = 44

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