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5 votes
find an equation for the nth term of a geometric sequence where the second and fifth terms are -8 and 512

User Stacii
by
8.4k points

1 Answer

3 votes

Answer:


n_x = -4n_(x-1)\\

where
n_1 = 2

Explanation:

512/-8 = -64

difference of n = 3


\sqrt[3]{64} = 4


n_x = -4n_(x-1)\\

where
n_1 = 2

User Allan Rwakatungu
by
8.1k points

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