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Using the following balanced equation:

2AI + 3H2SO4 → Al2(SO4)3 + 3H2
Given 3.56 g of Al how many grams of H2SO4 will also be required?
O 19.4 g H2SO4
O 5.34 g H2SO4
O 8.63 g H2SO4
0.00202 g H2SO4
0.653 g H2SO4

User Yotam Ofek
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1 Answer

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Answer:2Al(s) + 3H2SO4(aq) ==> Al2(SO4)3(aq) + 3H2(g) ... balanced equation

Using the stoichiometry of the balanced equation (2 mol Al : 3 mol H2SO4) and dimensional analysis, we can find the mass of Al needed to react with 26.5 ml of 0.542 M H2SO4.

Step-by-step explanation:

User Seren
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