Answer:
0.64 = 64% probability that they will be awarded the contract for either the Macon Expressway or the Seaview Expressway
Explanation:
We solve this question using these events as Venn sets.
I am going to say that:
Event A: Awarded the Macon Expressway.
Event B: Awarded the Seaview Expressway.
Probability that they will be awarded the Macon Expressway contract is 0.65
This means that
![P(A) = 0.65](https://img.qammunity.org/2022/formulas/mathematics/college/4to8x4wjwlvt53mhrbcjvj38pjgb2449e3.png)
The probability that they will be awarded the Seaview Expressway contract is 0.43.
This means that
![P(B) = 0.43](https://img.qammunity.org/2022/formulas/mathematics/college/6kbp63mm12o2vl4do76e0kuke6vzu1e8cb.png)
Furthermore, the probability that they will be awarded both contracts is 0.22.
This means that
![P(A \cap B) = 0.22](https://img.qammunity.org/2022/formulas/mathematics/college/j1kwxvld40hm4iywp1bujcut8yu4sqmuk9.png)
What is the
Probability that they will be awarded the contract for either the Macon Expressway or the Seaview Expressway?
Only A:
![P(A) - P(A \cap B) = 0.65 - 0.22 = 0.43](https://img.qammunity.org/2022/formulas/mathematics/college/1p2fy52d1mq01wcitb7rb89f3vgtlnfydw.png)
Only B:
![P(B) - P(A \cap B) = 0.43 - 0.22 = 0.21](https://img.qammunity.org/2022/formulas/mathematics/college/ui99s2gvfwrdvfa3uw1orpz1q03494ap0j.png)
Either
0.43 + 0.21 = 0.64
0.64 = 64% probability that they will be awarded the contract for either the Macon Expressway or the Seaview Expressway