Question

Can someone help me pls

Answer 1

See below

Explanation:

For seg FG to be tangent to the circle with center E, the side lengths 6, 10, 12 must follow the rule of Pythagorean triplets.

So,

`{10}^(2) + {6}^(2) = 100 + 36 = 136 \\ \\ {12}^(2) = 144 \\ \\ \because \: {10}^(2) + {6}^(2) \\eq \: {12}^(2) \\`

From above it is obvious that given segment lengths doesn't follow the Pythagorean triplet rule. Therefore, seg FG is not tangent to the circle with center E.