Answer:
Option A
Explanation:
Number of components assembled by the new employee per day,
N(t) =
![(50t)/(t+4)](https://img.qammunity.org/2022/formulas/mathematics/college/sf6cyio7w5yp67uh5gkazmmtbyiye3wszl.png)
Number of components assembled by the experienced employee per day,
E(t) =
![(70t)/(t+3)](https://img.qammunity.org/2022/formulas/mathematics/college/ivr1qf0u3m121v6zgxzw5e89xnde9ac4bs.png)
Difference in number of components assembled per day by experienced ane new employee
D(t)= E(t) - N(t)
D(t) =
![(70t)/(t+3)-(50t)/(t+4)](https://img.qammunity.org/2022/formulas/mathematics/college/jon10ssl95p8nl7ntsoyeec5tmdwha21qs.png)
=
![(70t(t+4)-50t(t+3))/((t+3)(t+4))](https://img.qammunity.org/2022/formulas/mathematics/college/ppm51g4zr7x8e6145z63ksuliswa2jd6r6.png)
=
![(70t^2+280t-50t^2-150t)/((t+3)(t+4))](https://img.qammunity.org/2022/formulas/mathematics/college/lcxq1a6v0jnbp5ts62rrq7tf5whm030xu6.png)
=
![(20t^2+130t)/((t+3)(t+4))](https://img.qammunity.org/2022/formulas/mathematics/college/5lomvqv486tprokhdp29nrkrdiwe9hgkjs.png)
=
![(10t(2t+13))/((t+4)(t+3))](https://img.qammunity.org/2022/formulas/mathematics/college/vo2ny69rx6jrzq93epc4o0hqgg964vats3.png)
Therefore, Option A will be the answer.