Question

Consider the figure shown below, find the value of
g


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Answer 1

Given:

A figure of a triangle.

To find:

The value of g.

Solution:

Law of Cosines:

`a^2=b^2+c^2-2bccosA`

Using the Law of Cosines for the given triangle, we get

`g^2=8^2+7^2-2(8)(7)cos(65^\circ)`

`g^2=64+49-112(0.4226)`

`g^2=113-47.3312`

`g^2=65.6688`

Taking square root on both sides.

`g=√(65.6688)`

`g=8.10363`

`g\approx 8.10`

Therefore, the value of g is about 8.10 units.