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Find the equation of the circle that has center (-4,3) and passes through 3,-3

1 Answer

4 votes

Answer:

(x+4)^2+(y-3)^2 = 85

Explanation:

The standard form of equation of a circle is expressed as;

(x-a)^2 + (y-b)^2 = r^2

(a, b) is the center

r iis the radius

Get the radius

Radius is the distance between the two points

r^2 = (-3-3)^2 + (3-(-4))^2

r^2 - (-6)^2+(7)^2

r^2 = 36+49

r^2 = 85

Substitute (-4, 3) and r^2 = 85 into the formula

(x-(-4))^2 + (y-3)^2 = 85

(x+4)^2+(y-3)^2 = 85

This gives the required equation

User ZMan
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