Question

Lol please help i literally cannot do math to save my life

Answer 1

3.6 units

Explanation:

Point A -->
`x_(1) \\` = -2 ,
`y_(1)` = 1

Point B -->
`x_(2)` = 1 ,
`y_(2)` = -1

AB =

`\sqrt{(x_(2) - x_(1))^2 + (y_(2) - y_(1))^2 } \\√([1 - (-2)]^2 + [(-1) - 1]^2) \\√(3^2 + (-2)^2) \\√(9 + 4) \\ √(13) \\3.605`

distance between AB can be rounded to 3.6 units

Hope it helps.

Answer 2

`\displaystyle d \approx 3.6`

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

Reading a Cartesian Plane

• Coordinates (x, y)

Algebra II

• Distance Formula:
  `\displaystyle d = √((x_2-x_1)^2+(y_2-y_1)^2)`

Explanation:

Step 1: Define

Find points from graph.

Point A(-2, 1)

Point B(1, -1)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

1. Substitute in points [Distance Formula]:
   `\displaystyle d = √((1+2)^2+(-1-1)^2)`
2. [Distance] [√Radical] (Parenthesis) Add/Subtract:
   `\displaystyle d = √((3)^2+(-2)^2)`
3. [Distance] [√Radical] Evaluate exponents:
   `\displaystyle d = √(9+4)`
4. [Distance] [√Radical] Add:
   `\displaystyle d = √(13)`
5. [Distance] [√Radical] Evaluate:
   `\displaystyle d = 3.60555127546`
6. [Distance] Round:
   `\displaystyle d \approx 3.6`