Question

6HCl(aq) + 2A1)

-
3H2(g) + 2AlCl3(aq)
1. How many moles of hydrogen are produced from 1.20 moles of aluminum?

Answer 1

Answer: 1.80 moles of
`H_2` will be produced 1.20 moles of aluminium.

Step-by-step explanation:

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}`

The balanced chemical reaction is:

`6HCl(aq)+2Al(s)\rightarrow 3H_2(g)+2AlCl_3(aq)`

According to stoichiometry :

2 moles of
`Al` produce = 3 moles of
`H_2`

Thus 1.20 moles of
`Al` will produce=
`(3)/(2)* 1.20=1.80moles` of
`H_2`

Thus 1.80 moles of
`H_2` will be produced 1.20 moles of aluminium.