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In ΔBCD, the measure of ∠D=90°, the measure of ∠B=31°, and CD = 1.6 feet. Find the length of BC to the nearest tenth of a foot.
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In ΔBCD, the measure of ∠D=90°, the measure of ∠B=31°, and CD = 1.6 feet. Find the length of BC to the nearest tenth of a foot.

User PaintedRed
by
4.6k points

2 Answers

5 votes

Answer:

3.1

Explanation:

User Haris Mehmood
by
4.8k points
5 votes

Answer:

3.1066≈3.1 feet

Explanation:

3.1066≈3.1 feet

User Spatulamania
by
4.7k points
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