Answer:
The mass of the exotic fruit is 20 grams.
Explanation:
For the system to be in equilibrium,
i. the resultant of all masses must be zero
ii. the total mass on the left of the hanger must be equal to that on the right
Thus,
84 g = 42 g + 42 g
mass of each carrot = 12 g
mass of each mushroom = 10 g
mass of each cherry = 2.5 g
mass of each strawberry = 5 g
So that;
On the left of the hanger,
(2 x 5) + (2 x 10) + 12 = 42
10 + 20 + 12 = 42
42 = 42
On the right of the hanger, let the mass of exotic fruit be represented by x.
x + 12 + 5 + (2 x 2.5) = 42
x + 12 + 5 + 5 = 42
x + 22 = 42
x = 20 g
The mass of the exotic fruit is 20 grams.