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For positive acute angles A and B it is known that sinA= 35/37 and tanB= 7/24. find the value of (A-B)
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For positive acute angles A and B it is known that sinA= 35/37 and tanB= 7/24. find the value of (A-B)

User Axel Kemper
by
3.2k points

1 Answer

3 votes

Answer:

54.8° to the nearest tenth of a degree

Explanation:

m∠A = arcsin 35/37 = 71.075...

m∠B = arctan 7/24 = 16.2602...

m∠A - m∠B = 71.075 - 16.260 = 54.8° to the nearest tenth of a degree

User James Woodall
by
3.7k points
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