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When a standard die is rolled, find the probability of getting a. 5 b. A number larger than 2 c. An odd number.

1 Answer

3 votes

Answer:

P(getting a 5)=
(1)/(6)

P(number larger than 2)=
(2)/(3)

P(numbers which are odd) =
(1)/(2)

Explanation:

When a standard die is rolled, we get sample space as {1,2,3,4,5,6}

So, let's use formula

P(E)=
(outcomes favorable to event E)/(Total number of outcomes)

For part A:

Event is getting a 5.

So, out of 6 samples , we get one 5 as outcome

So,

P(getting a 5)=
(1)/(6)

For part B:

The numbers larger than 2 are {3,4,5,6}

So, p(number larger than 2)=
(4)/(6) =(2)/(3)

P(number larger than 2)=
(2)/(3)

For part C:

The numbers which are odd are {1,3,5}

So, p(numbers which are odd)=
(3)/(6 ) =(1)/(2)

P(numbers which are odd) =
(1)/(2)

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