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A construction worker drops a hammer from 25m. How long will it take for the hammer to hit the ground? H(t)= -4.9t^2 +v +h

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Answer:

the time taken for the hammer to hit the ground is 2.26 s.

Explanation:

Given;

height through which the hammer falls, h = 25 m

The time taken for the hammer to hit the ground is calculated as;


h(t) = ut + (1)/(2) gt^2\\\\h(t) = 0 + (1)/(2) (9.8)t^2\\\\h(t) = 4.9t^2\\\\t = \sqrt{(h(t))/(4.9) } \\\\t = \sqrt{(25)/(4.9) } \\\\t = 2.26 \ s

Therefore, the time taken for the hammer to hit the ground is 2.26 s.

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