Question

How many liters of 0.10 M BaCl2 would be required to get 0.02 mol of BaCl2?

Answer 1

V = 0.2 L.

Explanation:

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In this case, according to the definition of molarity in terms of the moles of solute divided by the volume of the solution, it is possible for us to write:

M=n/V

Thus, given the moles and concentration of the solution, we can find the volume as shown below:

V=n/M

Therefore, we plug in the given data to obtain:

V = 0.02mol /(0.10mol/L)

V = 0.2 L

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