Answer:
4.018secs
Explanation:
Given the height reached by the test rocket by the expression
h(t) = -16t^2 +116t + 101 gives the
The rocket will reach the ground when h(t) = 0
Substitute h(t) = 0 into the expression
0 = -16t^2 +116t + 101
Multiply through by -1
16t^2 -116t - 101 = 0
Factorize using the general formula
t = 116±√(116)²-4(16)(-101)/4(16)
t = 116±√(13,456+6,464)/64
t = 116±√(19,920)/64
t = 116±141.138/64
t = 116+141.138/64
t = 257.138/64
t = 4.018secs
Hence it will take the rocket 4.018secs to reach the ground