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In triangle PQR, angle P and R are complementary angles where cos P =(0.3) what is the measure in degrees of angle R round to the nearest tenth

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Answer:


R = 17.5

Explanation:

Given

P and R are complementary


Cos\ P =0.3

Required

Find the measure of R


Cos\ P =0.3

Take arccos of both sides


P = cos^(-1)(0.3)


P = 72.5

Since P and R are complementary, then:


P + R = 90

Make R the subject


R = 90 - P

Substitute values for P


R = 90 - 72.5


R = 17.5

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