Question

How many Joules are required to raise the temperature of 50g of water from 20 to 100 degrees celsius?

Pls Help!!!!!​

Answer 1

Q = mcΔt

Step-by-step explanation:

Specific heat capacity of water = 4.18 J °C g

Mass of water = 50g

Δt = 100 - 20 = 80°C

Q = (50) x (4.18) x (80)

Q = 16720 J is required to raise the temperature of the water

Answer 2

Q = mcΔt

Q = 50 g x 4.184 J/g°c (100 - 20)°C

Q = 16736 J