Question

It takes 78.2 J of energy to raise the temperature of 45.6g of lead by 13 degrees celsius. What is the specific heat of lead?

Pls Help!!!! ​

Answer 1

Q = mcΔt but this time rearrange to find for c

Step-by-step explanation:

Q or energy = 78.2J

mass of lead = 45.6g

Specific heat capacity of lead = ????

Δt = 13°C

Q = mcΔt

Rearrange the equation to find for c

c = Q / m x Δt

c = (78.2) / (45.6) x (13)

c ≈ 0.132 J °C