Question

By titration, it is found that 68.1 mL of 0.143 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentration of the HCl solution.

Answer 1

Easy question to answer, you have the concentration and volume of the base and you have the volume of the acid. You need to find the concentration of the acid. C1V1 = C2V2 equation can be used here

Step-by-step explanation:

Volume of NaOH = 0.0681 L (change mL into L)

Concentration or Molarity of NaOH = 0.143 mol/L

Volume of HCl = 0.025 L (change mL into L)

Concentration or Molarity of HCl = ???

C1V1 = C2V2

Rearrange equation to find C2

(C1 * V1) / V2 = C2

(0.143 * 0.0681) / (0.025)

C2 = 0.389532

Concentration or Molarity of HCl = 0.389 mol/L