Question

Determine which are the zeros of p(x) = 9x^3 + 182^2 - x - 2​

Answer 1

x = -2 or x = -1/3 or x = 1/3

Explanation:

9x³ + 18x² - x - 2​ = 0

9x²(x+2) - (x+2) = 0

(x+2)(9x²-1)=0

(x+2)(3x+1)(3x-1)=0

x = -2 or x = -1/3 or x = 1/3