Question

What is an equation of the line that passes through the points (-3, 7) and (3, 3)?

Answer 1

`y = -(2)/(3)x + 5`

Explanation:

First you have to find the slope

`m = (7 - 3)/(-3 - 3) = (4)/(-6) = -(2)/(3)`

Now use the point-slope form by using one of the points and the slope. Let's use the point (3, 3)

`y - 3 = -(2)/(3) (x - 3)`

Multiply thru the equation by 3 to remove the fraction

3y - 9 = -2(x - 3) =

3y - 9 = -2x +6

3y = -2x + 15

`y = -(2)/(3)x + 5` is the equation in slope-intercept form