137k views
2 votes
Thomas has $30 to spend at the amusement park. Rides cost $2 each and admission at the gate is $6. What is the maximum number of rides that Thomas can go on?

A.2r + 6 < 30

B.2r + 6 = 30

C.6r + 2 = 30

D. 6r + 2 > 30

User Wiingaard
by
7.9k points

2 Answers

4 votes

Answer:

B.2r+6=30

Explanation:

It costs $6 dollars just to get in. Subtract 6 from 30. 30-6=24

Divide 24 by 2. 24 divided by 2 equals 12.

User Wilian
by
8.5k points
5 votes

Let the number of rides = r

Multiply the price per ride by number of rudest over 2r, you then add the admission to that to get 2R + 6

He has $30 so the total he can spend has to be less than or equal to $30

2r + 6 <= 30

The closest answer is A.

User Burjua
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories