Question

If a parabola has x-intercepts at 13 and -21, what is the x-coordinate of its vertex

Answer 1

-4

Explanation:

To find the x-coordinate of the vertex of a parabola given its x-intercepts, find the average of the x-intercepts:

x-coordinate of the vertex =
`(x_1+x_2)/(2)` (where
`x_1` and
`x_2` are the x-intercepts)

Plug in the x-intercepts 13 and -21

`(13+(-21))/(2)\\= (13-21)/(2)\\= (-8)/(2)\\=-4`

Therefore, the x-coordinate of the vertex is -4.

I hope this helps!