Question

PLS HELP ASAP i really need an answer a correct one

Answer 1

Answer: 67.23 L

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

Putting in the values we get:

`\text{Number of moles of methane}=(48g)/(16g/mol)=3moles`

1 mole of methane occupies = 22.4 L

Thus 3 moles of methane occupy =
`(22.4)/(1)* 3=67.23L`

Thus volume of 48 grams of methane gas is 67.23 L