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A 40 kg box is being pushed on a horizontal surface. The coefficient of kinetic friction between the box and the ground is 0.25. What horizontal force must be exerted on the box for it to accelerate at
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A 40 kg box is being pushed on a horizontal surface. The coefficient of kinetic friction between the box and the ground is 0.25. What horizontal force must be exerted on the box for it to accelerate at 1.2 m/s^2?

User DrBloodmoney
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1 Answer

5 votes

Answer:

Step-by-step explanation:

Σf=m*a

Σf=40*1,2

Σf=48N

User Keith Neuse
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4.3k points
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