Question

Due in 30 help me please ​

Answer 1

1. Fc = 14212.3 N = 14.21 KN

2. ac = 1579.14 m/s²

Step-by-step explanation:

First, we will find the linear velocity of the ball:

`v = r\omega`

where,

v = linear velocity = ?

r = radius of circle = 2.5 m

ω = angular speed = (4 rotations/s)(2π rad/1 rotation) = 8π rad/s

Therefore,

`v = (2.5\ m)(8\pi\ rad/s)\\v = 62.83\ m/s\\`

2.

Now, the centripetal acceleration can be given as:

`a_(c) = (v^2)/(r)`

where,

ac = centripetal acceleration = ?

Therefore,

`a_(c) = ((62.83\ m/s)^2)/(2.5\ m)`

ac = 1579.14 m/s²

1.

The centripetal force can be given as:

`F_(c) = ma_(c)\\F_(c) = (9\ kg)(1579.14\ m/s^2)\\`

Fc = 14212.3 N = 14.21 KN