Question

asked Jan 28, 2022 197k views

1 Answer

Cisum Inas · Answer 1 · 2022-02-02T15:16:04+0000

Given:

The equation is

$y=\log_2x$

The domain is
$\{\frac{1}2, 1, 2, 4, 8, 16\}$ .

To find:

The graph of six points that would satisfy the equation.

Solution:

We have,

$y=\log_2x$

For
x=(1)/(2) ,

$y=\log_2(1)/(2)$

$y=\log_22^(-1)$

y=-1
$[\because \log_aa^x=x]$

Similarly, at x=1,

$y=\log_22^0$

y=0

At x=2,

$y=\log_22^1$

y=1
$[\because \log_aa^x=x]$

At x=4,

$y=\log_22^2$

y=2
$[\because \log_aa^x=x]$

At x=8,

$y=\log_22^3$

y=3
$[\because \log_aa^x=x]$

At x=16,

$y=\log_22^4$

y=4
$[\because \log_aa^x=x]$

Plot the points
on a coordinate plane as shown below.

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