Answer:
(1.307 ; 3.893)
Explanation:
Given that:
Mean, xbar = 2.6
Standard deviation, s = 0.69
Sample size, n = 5
Confidence interval : xbar ± margin of error
Margin of Error = Tcritical * s/sqrt(n)
Degree of freedom (df) = n - 1 = 5 - 1 = 4
Hence Tcritical = 3.747
Margin of Error = 3.747 * 0.69/sqrt(4)
Margin of Error = 1.293
Lower boundary = (2.6 - 1.293) = 1.307
Upper boundary = (2.6 + 1.293) = 3.893
(1.307 ; 3.893)