25,759 views
2 votes
2 votes
consider the function and then use calculus to answer the questions that follow 1 1/x 5/x^2 1/x^3 (a) Find the interval(s) where the function is concave up. (Enter your answer in interval notation,do not round). (b) Find the interval(s) where the function is concave down. (Enter your answer in intervalnotation, do not round).

User Ali Nadalizadeh
by
2.6k points

1 Answer

22 votes
22 votes

Answer:

a)
image

b)
image

Explanation:

From the question we are told that

The Function


image

Generally the differentiation of function f(x) is mathematically solved as


image


image

Therefore


image

Generally critical point is given as


image


image


image

Generally the maximum and minimum x value for critical point is mathematically solved as


image

Where

Maximum value of x


image

Minimum value of x


image

Therefore interval of increase is mathematically given by


image


image

Therefore interval of decrease is mathematically given by


image

Generally the second differentiation of function f(x) is mathematically solved as


image

Generally the point of inflection is mathematically solved as


image


image

Therefore inflection points is given as


image


image

a)Generally the concave upward interval X is mathematically given as


image


image

b)Generally the concave downward interval Y is mathematically given as


image

User Jaswanth
by
2.7k points