Question

At noon Joyce drove to the lake at 30 miles per hour. but she made the long walk back home at 4 miles per hour. How long did she walk if she was gone for 17 hours? How far did she walk?

PLEASE GIVE A REAL ANSWER , WILL GIVE BRANILIEST

Answer 1

Distance be x

• Time=Distance/Speef

So

• T_1=x/30
• T_2=x/4

ATQ

`\\ \tt\hookrightarrow T_1+T_2=17`

`\\ \tt\hookrightarrow x/30+x/4=17`

`\\ \tt\hookrightarrow 2x+15x/60=17`

`\\ \tt\hookrightarrow 17x=1020`

`\\ \tt\hookrightarrow x=60mi`

Answer 2

60 miles

Explanation:

let d = distance to the lake

Using: time = distance ÷ speed

Create expressions for the time it takes for each journey:

Drive:
`t_1=(d)/(30)`

Walk:
`t_2=(d)/(4)`

If total time = 17 hours

`\implies t_1+t_2=17`

`\implies (d)/(30)+(d)/(4)=17`

`\implies (17d)/(60)=17`

`\implies 17d=1020`

`\implies d=(1020)/(17)`

`\implies d=60`

Therefore she walked 60 miles