Question

A polynomial P has zeros when x=0, x=-1/6 and x=-3 Whats could be the equation p?

Answer 1

P(x) =
`x^(3)` +
`(19)/(6) x^(2)` +
`(1)/(2) x`

Explanation:

x(x + 1/6)(x + 3) = P

x(
`x^(2)` + 3x + 1/6(x) + 1/2) = P

x (
`x^(2)` + 19/6(x) + 1/2) = P

`x^(3)` +
`(19)/(6) x^(2)` +
`(1)/(2) x` = P(x)