Question

Im new can anyone help

Answer 1

We have the equation:

`W = W_0*((1)/(2))^(0.36*t)`

Where:

W₀ is the initial area of the wound, and t is the time in days.

Now, if we initially have a wound of 25 mm^2, then:

W₀ = 25mm^2

And we can replace it in the equation, then we get:

`W = (25mm^2)*((1)/(2))^(0.36*t)`

We want to know the size of this wound after:

a) 1 day.

We know that t represents time in days, so here we just need to replace t by one, then:

`W = (25mm^2)*((1)/(2))^(0.36*1) = 19.5 mm^2`

b) 1 week

Again, t represents the time in days, so we need to write this in days.

We know that:

1 week = 7 days.

then t = 7

The size of the wound after 7 days is:

`W = (25mm^2)*((1)/(2))^(0.36*7) = 4.36 mm^2`