A 500 kg crate is pushed horizontally with a force of 1500 N. If the coefficient of friction is 0.25, calculate the acceleration of the crate.

asked Apr 6, 2022 131k views

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$ma=F-fmg\\a=(F-fmg)/(m)=(1500-0.25*500*10)/(500) =(1)/(2)[(m)/(s^2)]$

Nekeniehl answered Apr 11, 2022

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