Question

A study of fox rabies in southern Germany gave information about different regions and the occurrence of rabies in each region. A random sample of 16 locations in Region 1 yielded a mean of 4.75 cases of rabies with a standard deviation of 2.8 cases. An independent sample of 15 locations in Region 2 yielded a mean of 3.93 cases with a standard deviation of 2.4 cases. If you want to test whether the average number of rabies cases in Region 1 is greater than the average number of rabies cases in Region 2, which is the appropriate Data Analysis tool

Answer 1

Two independent sample t test

Explanation:

The research described describes the statistics of two different samples which are also independent,

Sample 1 :

Sample size, n1 = 16

Mean, xbar = 4.75

Standard deviation s2 = 2.8

Sample 1 :

Sample size, n1 = 15

Mean, xbar = 3.93

Standard deviation s2 = 2.4

The hypothesis :

H0 : μ1 = μ2

H1 : μ1 ≠ μ2

The t statistic :

(xbar1 - xbar 2) ÷ sqrt[(s1²/n1 + s2²/n2)

From on the test statistic, obtain the p value and compare with Given α - value to make and conclude in a decision.