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Which equation of an exponential function has a graph that passes through the points

(1,5) and (2,15)?

User Owsata
by
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1 Answer

1 vote

Answer:


y = (5)/(3) (3^(x) )

Explanation:

In general,
y = k(b^(x))

Substitute x = 2, y = 15

(1)
15 = kb^(2)

Substitute x = 1, y = 5

(2)
5 = kb^(1) = kb

Divide equation (1) by equation (2)


(15 = kb^(2) )/(5= kb )

3 = b

Now substitute b = 3 in equation (2) to find k

5 = k(3)


k = (5)/(3)

Since we know the values for k and b, we now have the exponential function that passes thru (1, 5) and (2, 15)


y = (5)/(3) (3^(x) )

User Samthegolden
by
7.3k points