Answer
33
Explanation:
11 of the faces is a square.
\begin{aligned} \text{Area of a square} &= \text{side} \cdot \text{side}\\\\ &= 3 \cdot 3\\\\ &= {\blueD{9}} \\\\ \end{aligned}
Area of a square
=side⋅side
=3⋅3
=9
Hint #22 / 4
444 of the faces are triangles. Each triangle has the same base and height.
\begin{aligned} \text{Area of a triangle} &= \dfrac12 \cdot \text{base} \cdot \text{height}\\\\ &= \dfrac12 \cdot 3 \cdot 4\\\\ &= 6 \\\\ \end{aligned}
Area of a triangle
=
2
1
⋅base⋅height
=
2
1
⋅3⋅4
=6
The total area of these 444 triangles is 4 \cdot 6 = \greenD{24}4⋅6=244, dot, 6, equals, start color #1fab54, 24, end color #1fab54.
Hint #33 / 4
Let's add the areas we found to find the surface area.
\begin{aligned} \text{Surface area} &= \blueD{9}+ \greenD{24}\\\\ &= 33\\\\ \end{aligned}
Surface area
=9+24
=33
Hint #44 / 4
The surface area of this square pyramid is 333333 units^2
2
squared.