Answer:
The calculated value t = 3.050 < 3.8325 at 0.0025 level of significance
The null hypothesis is accepted
The sample data support the claim that shelf life has increased.
Explanation:
Step(i):-
Given that the Mean of the Population = 216days
Given that sample size n=9
Given that mean of sample x⁻ = 217.222 days
Given that the Standard deviation of the sample (S) = 1.2019days
Step(ii):-
Null hypothesis:-H₀:The sample data support the claim that shelf life has increased.
Alternative Hypothesis:H₁: The sample data support the claim that shelf life has decreased
Test statistic
t = 3.050
Degrees of freedom γ = n-1 = 9-1 =8
t₀.₀₂₅ = 3.8325
Final answer:-
The calculated value t = 3.050 < 3.8325 at 0.0025 level of significance
The null hypothesis is accepted
The sample data support the claim that shelf life has increased.