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37 votes
Find the triangular number in the nth position if n is. a)22 (b)11 (c)31 (d)40​

User Pablo Rincon
by
2.2k points

2 Answers

23 votes
23 votes

Answer:

a) 253

b) 66

c) 496

d) 820

Step-by-step explanation:

Triangular numbers : pattern of numbers that form equilateral triangles. Each subsequent number in the sequence adds a new row of dots to the triangle.

nth triangular number formula:
T_n=(n(n+1))/(2)

a) if n = 22


T_(22)=(22(22+1))/(2)=253

b) if n = 11


T_(11)=(11(11+1))/(2)=66

c) if n = 31


T_(31)=(31(31+1))/(2)=496

d) if n = 40


T_(40)=(40(40+1))/(2)=820

User Rcarvalho
by
2.7k points
17 votes
17 votes

Answer:

  • Shown below.

Step-by-step explanation:

use the formula: n(n+1)/2

where n is the number of nth position

(a)

n(n+1)/2

22(22+1)/2

253

(b)

11(11+1)/2

66

(c)

n(n+1)/2

31(31+1)/2

496

(d)

n(n+1)/2

40(40+1)/2

820

User NilColor
by
3.1k points