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A 2.60 kg block is in equilibrium on an incline of 24.3◦ . The acceleration of gravity is 9.81 m/s 2 . What is Fn of the incline on the block? Answer in units of N.
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29 votes
29 votes
A 2.60 kg block is in equilibrium on an incline

of 24.3◦
.
The acceleration of gravity is 9.81 m/s
2
.
What is Fn of the incline on the block?
Answer in units of N.

User Caiuspb
by
1.9k points

1 Answer

20 votes
20 votes

Answer:

W = m g = 2.60 * 9.81 = 25.5 N weight of block

Fn = W cos theta = 25.5 N * cos 24.3 = 23.2 N normal force of plane

User Debnath Sinha
by
3.0k points
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