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A leaky valve on the water meter overcharges Ahmed for one Liter of water for every 2 months. The overcharged amount w varies directly with time t . (a) Find the equation that models the variation . (b) Solve the equation to find the number of months it will take for Ahmed to be overcharged for 10 liters of water leaked. Show all your steps

User Jei
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1 Answer

4 votes

Answer:

20 months

Explanation:

A leaky valve on the water meter overcharges Ahmed for one Liter of water for every
2 months. The overcharged amount
w varies directly with time
t.

(a)

As the overcharged amount
w varies directly with time
t,


w=kt

Here,
k is a constant.

A leaky valve on the water meter overcharges Ahmed for one Liter of water for every
2 months.

Put
w=1\,,\,t=2


1=2k\\k=(1)/(2)

So,


w=(t)/(2)

(b)

To find the number of months it will take for Ahmed to be overcharged for 10 liters of water leaked, put
w=10 in
w=(t)/(2)


10=(t)/(2)\\\\t=10(2)\\


t=20 months

User Jake Wagner
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