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40 votes
40 votes
1. Find the area of the composite figure to the nearest hundredth.

2. Find the area of the shaded region to the nearest tenth.

1. Find the area of the composite figure to the nearest hundredth. 2. Find the area-example-1
1. Find the area of the composite figure to the nearest hundredth. 2. Find the area-example-1
1. Find the area of the composite figure to the nearest hundredth. 2. Find the area-example-2
User Uhsac
by
2.8k points

2 Answers

22 votes
22 votes

Answer:

#1: 751.56 mm²

#2: 477 km²

Explanation:

First I noted the semicircle on the left, which has a radius of 12.5 mm. The formula for finding the area of a semicircle is 1/2(πr²).

1/2(3.14 * (12.5)²)

12.5 squared is 156.25.

1/2(3.14 * 156.25)

Multiply 3.14 by 156.25 to get 490.625.

1/2(490.625)

Divide 490.625 by 2 to get 245.3125.

245.3125 mm² for the semicircle

Then, I split the rest of into a 12.5 by 25 rectangle and a 31 by 12.5 triangle.

(12.5 * 25) + 1/2(31 * 12.5)

Multiply 12.5 by 25 to get 312.5.

312.5 + 1/2(31 * 12.5)

Multiply 31 by 12.5 to get 387.5.

312.5 + 1/2(387.5)

Multiply 1/2 by 387.5 to get 193.75

312.5 + 193.75

Add 312.5 and 193.75 to get 506.25.

506.25 mm² for the rest of the figure.

Now add the two measures, and you have your answer for #1.

245.3125 + 506.25 = 751.5625 mm², which rounds to 751.56 mm².

The area of the composite figure is 751.56 mm².

Now for #2. First, find the area of the triangle.

1/2(40 * 27)

Multiply 40 by 27 to get 1080.

1/2(1080)

Multiply 1/2 by 1080.

590 km² for the triangle.

Now find the area of the circle.

3.14 * 6²

3.14 * 36

113.04 km² for the circle.

Now subtract the area of the circle from the area of the triangle.

590 - 113.04

476.96 km², which rounds to 477.0 km².

The area of the shaded region is 477 km².

User Yashdeep Patel
by
2.7k points
25 votes
25 votes

Answer:

  • 1. 745.31 mm²
  • 2. 426.96 km²

Explanation:

#1

We can separate the figure into 3 parts and sum the areas.

Semicircle with radius 12.5 mm:

  • A = 1/2(πr²) = 1/2(3.14*12.5²) = 245.31 mm²

Rectangle with sides 12.5 mm and its double size:

  • A = 12.5*(2*12.5) = 312.5 mm²

Triangle with height 12.5 mm and base 30 mm:

  • A = 1/2*(55 - 2*12.5)*12.5 = 187.5 mm²

Sum of the three:

  • 245.31 + 312.5 + 187.5 = 745.31 mm²

#2

The shaded region is the difference of the areas of the triangle and the circle

Triangle:

  • A = 1/2*27*40 = 540 km²

Circle:

  • A = πr² = πd²/4 = 3.14*12²/4 = 113.04 km²

Shaded region:

  • 540 - 113.04 = 426.96 km²
User Jpishko
by
3.3k points